Non-algebraic proofs of Pythagoras' theorem:
- First an animation. Although it might not be strictly a proof, it's a great demonstration. (Alternate local copy.)
- Then a more thorough proof by tiling. A little less accessible, though.

I want to do geometric proofs! For example,

Is this a proof?

cd
aacad
bbcbd
a+b(a+b)(c+d)
c+d


Oh, and blah blah Pope blah.
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From: [identity profile] sigmonster.livejournal.com


A defining property of 1 (the identity in an algebraic system) is 1 \times r = r \times 1 = r, for any object r in the system. (Even for non-commutative systems, like matrix multiplication, the identity always commutes.)

So if there are two identities, 1_a and 1_b, we can write

1_a = 1_a \times 1_b = 1_b

and they are the same!
ext_79424: Line drawing of me, by me (Default)

From: [identity profile] spudtater.livejournal.com


That proves that 1_a and 1_b have the same numeric value. It doesn't prove that they are identical.

From: [identity profile] sigmonster.livejournal.com


Hoh yus it does, sunshine. I'm using the strongest possible value of equals (in the given system), *both in the definition and in the equation*, which is identity (in the given system). Ought to be the triple parallel line symbol, really.

Otherwise you'd be saying that 1 \times r and r are not identical. As a matter of typography, that's trivially true - but there is no way at all to distinguish them by the algebraic rules, so we call them identical in that system.

We're getting into some deep waters, here...

From: [identity profile] sigmonster.livejournal.com


Just had another quick thought - this is also the reason 1 isn't a prime; you can tag on 1 \times 1 \times 1 ... and still have the identical integer, so you lose unique prime factorisation. In larger fields, you specify unique prime factorisation *up to units* (where a unit has a multiplicative inverse, basically).
ext_79424: Line drawing of me, by me (Default)

From: [identity profile] spudtater.livejournal.com


Er... oh... okay.
Guess I wasn't taking 'defining property' as literally as I should have been.

From: [identity profile] sigmonster.livejournal.com


It's all consistent, and it all fits the real numbers and their extensions. It doesn't have to make sense.

See also: Proof by Intimidation.
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